Comments on: JSON Parsing in android

By: Cowtowncoder

Cowtowncoder — Sat, 04 Sep 2010 04:49:16 +0000

I am not sure it really makes sense to use the default JSON parser (one from json.org) — it is very clumsy, inefficient and lots of code to write. Rather, packages like Gson and Jackson make JSON handling much much more convenient. So while tutorials are good, I really wish they actually tried to show best practices and not just arbitrary ways.

By: Chris Dawson

Chris Dawson — Mon, 26 Jul 2010 17:31:22 +0000

Doh, actually the second line should be:

String theError = jObject.getString(“error”);

By: Chris Dawson

Chris Dawson — Mon, 26 Jul 2010 17:29:49 +0000

@Pedro Teixeira Pedro, hopefully you figured this out, but the testing variable you are passing into JSONArray is not an array but a hash (or associative array). If you were to use ['error', 'empty'] then it would parse, but I don't think that is what you want to do. If I understand your intention correctly, you want to retrieve the "empty" value from this hash by specifying the key "error". To do this, use this code: jObject = new JSONObject(testing); String theError = (String)jObject.getJSONObject("error"); Now, theError should have the correct value of "empty".

By: Andrew

Andrew — Tue, 20 Jul 2010 19:53:28 +0000

I wrote up a very extensive tutorial on using JSON in Android (that also deals with best practices for downloading files using Android) that I think would be very, very helpful to anyone using this page. You can find it here:
http://blog.andrewpearson.org/2010/07/android-why-to-use-json-and-how-to-use.html

By: Pedro Teixeira

Pedro Teixeira — Thu, 17 Jun 2010 18:39:07 +0000

Hello,

I have this JSON String:

testing = {“error”:”empty”}

It’s on a correct format right?

When I try to put it on an JSON Array

CODE: SELECT ALL
info = new JSONArray(testing);

I always get this JSON Exception:
CODE: SELECT ALL
org.json.JSONException: A JSONArray text must start with ‘[' at character 1 of {"error":"empty"}

I mean.. the String is already in the JSON String format so I really don't understand what's going on. I tried to append the ''[]” it doesn’t give me the exception anymore, but I’m also not able to retrieve the values I want in this case info.getString(0) which would give me the ”error”.

Does anyone have any ideia what I’m doing wrong? I’ve been through JSON parsing tutorials, and I’m doing like they say…

By: hany

hany — Sat, 24 Apr 2010 10:18:43 +0000

Thanks , this tutorial helped me a lot.

By: Stephan Celis

Stephan Celis — Tue, 20 Apr 2010 07:36:52 +0000

Thanks this tutorial helped me a lot. Great share.

By: Shyam

Shyam — Tue, 13 Apr 2010 10:00:27 +0000

@Michel thanks Michel

By: Michel

Michel — Wed, 31 Mar 2010 10:02:12 +0000

Great!

very good example